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5x^2+18x+35=-22x
We move all terms to the left:
5x^2+18x+35-(-22x)=0
We get rid of parentheses
5x^2+18x+22x+35=0
We add all the numbers together, and all the variables
5x^2+40x+35=0
a = 5; b = 40; c = +35;
Δ = b2-4ac
Δ = 402-4·5·35
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-30}{2*5}=\frac{-70}{10} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+30}{2*5}=\frac{-10}{10} =-1 $
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